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Hi!
First of all, FANTASTIC EXTENSION... thanx!!
Second, I'm a musician, not a programmer, so my mistakes are probably for ignorance, but
my problem is on WHERE section:
I have a column named "organico" and in it are written some records like "Lirico".
I need to show a grid where there are all the composition that match with "Lirico".
I tried to write in the inputbox:
WHERE `organico`=`Lirico` or
WHERE organico=Lirico or
`organico`=`Lirico` or
organico=Lirico
Ok, I really don't know how to write this... please show me how...
Thanks in advance
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Hi,
hope you are not a gambler Non of your choices are correct...
Please try:
WHERE organico = 'Lirico'
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I tried, but anything again...
i put in the inputbox
WHERE repertorio = `Lirico`
(repertorio is the new name of the field in the DB)
but nothing happens...
Well, if I don't use that advance condition the grid shows me correctly the columns I need; with the WHERE conditions it doesn't show anything... WHY?
Can you suggest me some particular configuration?
I can't upload the image I did... I fill diot..
Sorry!!
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Hi,
be careful when you are using this
`
'
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Thank you viljem for your reply,
I tried your way, right copying your code directly to the inputbox...
It still not working, and I don't know what to do...
Well, I'm learning how Table JX works, and I hope during this time I'll understand what I'm doing wrong...
Thanx in advance for any suggestion!
Stefano
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SOLVED!!!!
trying and trying...
WHERE has not to be repeated in the inputbox!
in the inputox I've written repertorio = 'lirico' and now it works
It works also with `repertorio` = 'lirico'
yes I did 2 mistakes:
put WHERE inside the inputbox, and using the
`
'
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